Question 1193624
Diagonals of rhombus bisect each other at right angles

In {{{(triangle) AEB }}}

AB=6 EB = 1/2 * DB =3

AB^2-EB^2= AE^2

6^2-3^2= 27

AE = {{{3sqrt(3)}}}

AC = 2* AE = {{{6sqrt(3)}}}

*[illustration rhombus.png].