Question 1202717
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Solve for y
{{{-3y + 6x = -6}}}


{{{-3y =  -6x-6}}}


{{{y =  (-6x-6)/(-3)}}}


{{{y =  (-6x)/(-3)+(-6)/(-3)}}}


{{{y =  2x+2}}}


Compare this to the template y = mx+b
m = 2 = slope
b = 2 = y intercept


Let's plug in x = 0
{{{y =  2x+2}}}


{{{y =  2*0+2}}}


{{{y =  0+2}}}


{{{y =  2}}}
We have x = 0 map to y = 2
The point (0,2) is on the line.


Now let's try x = 1
{{{y =  2x+2}}}


{{{y =  2*1+2}}}


{{{y =  2+2}}}


{{{y =  4}}}
The point (1,4) is also on the line.


Repeat those steps for x = 2, x = 3, x = 4,and x = 5.
We get this table
<table border = "1" cellpadding = "5"><tr><td>x</td><td>y</td></tr><tr><td>0</td><td>2</td></tr><tr><td>1</td><td>4</td></tr><tr><td>2</td><td>6</td></tr><tr><td>3</td><td>8</td></tr><tr><td>4</td><td>10</td></tr><tr><td>5</td><td>12</td></tr></table>
Each time x goes up by 1, y increases by 2. This is because slope = 2.
The table can be as big or small as you want.


Graph
{{{
drawing(400,400,-3,7,-2,14,
graph(400,400,-3,7,-2,14,-100,2x+2),
circle(0,2,0.05),circle(0,2,0.1),circle(0,2,0.15),circle(1,4,0.05),circle(1,4,0.1),circle(1,4,0.15),circle(2,6,0.05),circle(2,6,0.1),circle(2,6,0.15),circle(3,8,0.05),circle(3,8,0.1),circle(3,8,0.15),circle(4,10,0.05),circle(4,10,0.1),circle(4,10,0.15),circle(5,12,0.05),circle(5,12,0.1),circle(5,12,0.15),

locate(0+0.3,2,"(0,2)"),locate(1+0.3,4,"(1,4)"),locate(2+0.3,6,"(2,6)"),locate(3+0.3,8,"(3,8)"),locate(4+0.3,10,"(4,10)"),locate(5+0.3,12,"(5,12)")
)}}}
The points 
(0,2)
(1,4)
(2,6)
(3,8)
(4,10)
(5,12)
are marked on the graph.
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