Question 1167309
<pre>
tim did 10 lunges on day 1 and continued this doing 4 more lunges on each day.on day 7th he took a break and did nt do any day day.what is the equation for this? express it in the form y=ax(x+b)+c, where a,b and c are constants.x= no of days and y=no of lunges tim did

I don't believe the x in ax belongs there. So, instead of y = ax(x + b) + c, it should be y = a(x + b) + c

Now, this is an Arithmetic Progression (A.P.) with the following formula: {{{matrix(1,3, a[n], "=", a[1] + (n - 1)d)}}}, where:
                                                                          {{{a[n]}}} is the value of the n<sup>th</sup> term                                                                           
                                                                          {{{a[1]}}} is the 1<sup>st</sup> term (10, in this case)
                                                                          {{{n}}} is the term number
                                                                          {{{d}}} is he common difference (4, in this case)
                                                             {{{matrix(3,3, a[n], "=", a[1] + (n - 1)d, a[n], "=", 10 + (n - 1)4, a[n], "=", 4(n - 1) + 10)}}}
In the form y = a(x + b) + c, {{{matrix(1,3, a[n], "=", 4(n - 1) + 10)}}} translates to <font color = red><font size = 4><b>y = 4(x - 1) + 10</font></font></b>, with a, b, and c being constants
4, - 1, and 10, respectively. With him taking a break on day 7, he only did lunges for 6 days, so x would range from 1 - 6.

I'm TOTALLY CONFUSED as to what the other person did. His/her equation seems EXTREMELY weird!!!</pre>