Question 113989
{{{y^2=-4x}}}

Convert this to the standard equation for a parabola  {{{(y-k)^2=4p(x-h)}}} that has a vertex at (h,k), focus at (h+p,k), and directrix at x = -p


{{{(y-0)^2=4(-1)(x-0)}}}

So, k = 0, h = 0, and p = -1


1.  Vertex:  (0, 0)
2.  Focus:   (-1,0)
3.  Directrix: x=1