Question 1202569
i think this might follow a poisson distribution.
the formula for poisson distribution is p(x) = e^-L * L^x / x!
e is the scientific constant of 2.718281828.
L is the mean number of occurrences = 3
x will be  1 and / or 2.


a. exactly one mistake:


formula becomes p(1) = e^-3 * 3^1 / 1! = .1493612081.


b. at most two mistakes.


p(0) = e^-3 * 3^0 / 0! = .0497870684
p(2) = e^-3 * 3^2 / 2! = .2240418077.
at most 2 mistakes is equal to p(0) + p(1) + p(2) = .0497870684 + .1493612081 + .2240418077 = .4231900811.


the online calculator at <a href = "https://homepage.divms.uiowa.edu/~mbognar/applets/pois.html" target = "_blank">https://homepage.divms.uiowa.edu/~mbognar/applets/pois.html</a> can do the calculsations for you.


here are the results from using that calculator.


<img src = "http://theo.x10hosting.com/2023/060411.jpg">


<img src = "http://theo.x10hosting.com/2023/060412.jpg">


<img src = "http://theo.x10hosting.com/2023/060413.jpg">


<img src = "http://theo.x10hosting.com/2023/060414.jpg">