Question 1202653
<pre>
Here's one exactly like it.  It can be done with 1 unknown or 2 unknowns. It
is easier to set up in two unknowns.  Maybe another tutor will solve it using
only one unknown.  Here is the problem I solved with different numbers, using
two unknowns:</pre>
The admission fees at an amusement park are $3.10 for children and $5.80 for
adults. On a certain day, 443 people entered the park, and the admission fee
collected totaled $2,051.00. How many children and how many adults attended the
amusement park that day?<pre>
Let c = number of children
let a = number of adults

                          | money |
                          | taken |
         | number | price |  in   | 
children |    c   |  3.10 | 3.10c |
adults   |    a   |  5.80 | 5.80a |
-----------------------------------
totals   |  443   |-------| 2051  |

First equation from first column    c + a = 443
Second equation from last column  3.10c + 5.80a = 2051

{{{system(c+a=443,3.10c+5.80a=2051)}}}    

solve the first equation for c:

c = 443 - a

Substitute in the second equation:

  3.10(443 - a) + 5.80a = 2051

1373.30 - 3.10a + 5.80a = 2051

        1373.30 + 2.70a = 2051

                  2.70a = 677.70

                      a = 251

Substitute in

                      c = 443 - a

                      c = 443 - 251

                      c = 192

So there were 251 adults and 192 children.

Now do yours the exact same way.

Edwin</pre>