Question 1202586
{{{x^2-14x+10y+79=0}}}

note that {{{(14/2)^2=49}}} so use this to complete-the-square for the x terms.

{{{x^2-14x+49+10y+79-49=0}}}

{{{(x-7)^2+10y+30=0}}}

{{{(x-7)^2=-10y-30}}}

{{{highlight(-(x-7)^2=10(y+3))}}}------------this is a convenient form which you probably want.  Exactly what you need from this or the original equation, you should specify.

.

.







(adjusted)