Question 1202588
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(1) a+2b = 3c
(2) 2a+4b+c = 56<br>
In the second equation, "2a+4b" is "a+2b" times 2; and the first equation gives us the value of "a+2b" in terms of c:<br>
2a+4b+c = 56
2(a+2b)+c = 56
2(3c)+c = 56
6c+c = 56
7c = 56
c = 8<br>
ANSWER: (C) 8<br>