Question 1202526
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passing through the point (1,-2) and perpendicular to the line x+3y-6=0.
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Perpendicularity of the two lines means that this other line should be either {{{3x-y+k=0}}}, or {{{-3x+y+j=0}}}.  


Pick one of those and then substitute for the given required point and simplify.


{{{3x-y-(3*1-(-2))=0}}}

{{{3x-y-(3+2)=0}}}

{{{3x-y-5=0}}}----------------OR  {{{-3x+y+5=0}}}.