Question 114325
I suspect you left out an x in the 2nd term.  Put the equation in standard form:


{{{x^2+3x+24+0}}}


Then use the quadratic equation:  {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}



{{{x = (-3 +- sqrt( 3^2-4*1*24 ))/(2*1) }}}
{{{x=(-3+-sqrt(9-96))/2=(-3+-sqrt(-87))/2}}}
{{{x=(-3+i*sqrt(87))/2}}} or {{{x=(-3-i*sqrt(87))/2}}}


On the other hand, if you really meant what you wrote, {{{x^2+3=-24}}}, then


{{{x^2=-27}}}
{{{x=0+-sqrt(-27)}}}
{{{x=0+-i*sqrt(27)}}}
{{{x=0+-3i*sqrt(3)}}}
{{{x=3i*sqrt(3)}}} or {{{x=-3i*sqrt(3)}}}