Question 1202469
The 3rd term of a geometric sequence is 36, and the 6th term is 9/2. What is the recursive formula for the sequence


tn = ar^(n-1)

t3= a*r^(3-1)

t3= ar^2=36

t6 = a*r(6-1) = ar^5= 9/2

t3/t6  = ar^2/ar^5 = 36/(9/2)

1/r^3= 36/9 *2

1/r^3= 8
r^3= 1/8

r=1/2

ar^2=36

plug r

a*(1/2)^2 =36
a/4 =36
a= 144

tn = 144*(1/2)^n-1