Question 1202419
<br>
Here is an informal solution using logical reasoning and simple arithmetic.  Compare it to the solution from tutor @math_tutor2020 to see that the formal algebra does exactly what the informal solution does.<br>
Subtract the "extra" 293 $1 bills from the total, leaving equal numbers of $1 and $10 bills with a total value of $2900-$293 = $2607.<br>
The total value of one $1 bill and one $10 bill is $11.<br>
So the number of bills of each kind remaining is $2607/$11 = 237.<br>
ANSWERS:
$10 bills: 237
$1 bills: 237+293 = 530<br>
CHECK: 237(10)+530(1) = 2370+530 = 2900<br>