Question 1202401
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<pre>

Let x be the number in the middle.

Then two other numbers are (x-2) and (x+2).


The sum of the three numbers is 

    (x-2) + x + (x+2) = 1368,

or

    3x = 1368

     x = 1368/3 = 456.


<U>ANSWER</U>.  The numbers are 454, 456 and 458.
</pre>

Solved.


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In the future, &nbsp;if you have such problem with different sum, &nbsp;simply divide
the sum by &nbsp;3: &nbsp;it will give you the middle number.


This simple trick works &nbsp;ALWAYS, &nbsp;saving your time.



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To see many other similar solved problems, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Problems-with-consecutive-odd-even-integers/Problems-with-consecutive-odd-even-integers.lesson>Problems with consecutive integer numbers; odd/even consecutive integer numbers</A>

in this site.


Learn the entire subject from there.