Question 115081
x-2y=0 or x=2y
now substitute 2y for x in the other equation & solve for y.
(2y)^2+y^2=16
4y^2+y^2=16
5y^2=16
y^2=16/5 
y=4/sqrt5 answer.
x-2(4/sqrt5)=0
x-8/sqrt5=0
x=8/sqrt5 answer.