Question 1202372
<pre>
{{{log(4,(8))+log(4,(32))-log(4,(2))}}} 

{{{log(4,(2^3))+log(4,(2^5))-log(4,(2))}}}

{{{3log(4,(2))+5log(4,(2))-log(4,(2))}}}

{{{7log(4,(2))}}}

Use formula {{{log(a,(b))=1^""/log(b,(a))}}}

{{{7/log(2,(4))}}}

{{{7/log(2,(2^2)))}}}

{{{7/(2log(2,(2)))}}}

{{{7/(2*1)}}}

{{{7/2)}}}

Edwin</pre>