Question 1202332
<br>
This kind of problem is often easier to solve by working backwards.  Here is a solution by that method.<br>
The bus finished with 60 passengers; that was after 20 people boarded it at the second stop.  So before those 20 passengers boarded, the number of passengers was 60-20 = 40.<br>
Upon arriving at that second stop, half the passengers got off the bus.  Since there were 40 left after half of them got off, the number on the bus upon arriving at the second stop was 40*2 = 80.<br>
At the first stop, 5 passengers got on the bus; so before those passengers got on the bus the number of passengers was 80-5 = 75.<br>
Upon arriving at the first stop, 1/4 of the passengers got off the bus; that means the 75 people on the bus before the other 5 got on was 3/4 of the number that had been on the bus upon arriving at the first stop.  3/4 of 100 is 75, so the original number of passengers, before arriving at the first stop, was 100.<br>
ANSWER: 100<br>