Question 1202331
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Ten years ago Linda was three times Christy's age then. Ten years from now 
Christy's age will be 4/7 of Linda’s age then. How old are they now.
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            I read, interpret and solve the problem in different way;

            so my numbers are different from that of @mananth.



<pre>
Let x years be the Christy's age 10 years ago;
then Linda's age at that time was 3x years.


Ten years from now Christy's age will be  (x+20) years;
                   Linda's   age will be (3x+20) years then.


So, I write equation as the problem states

    x + 20 = {{{(4/7)*(3x+20)}}}.


Simplify and find x

    7x + 140 = 12x + 80

    140 - 80 = 12x - 7x

       60    =    5x

        x    =    60/5 = 12.


<U>ANSWER</U>.  Christy's age now is 12+10 = 22 years.  Linda's age now is 3*12+10 = 46 years.


<U>CHECK</U>.   You may check it on your own that the condition of the problem 
         "in ten years" is satisfied.
</pre>

Solved.