Question 1202323
Two boats A and B left a port C at the same time on different routes. 
B travelled on a bearing of 150° and A travelled on the north side of B. When A had travelled 8 km and B had travelled 10 km, the distance between
the two boats was found to be 12 km. Calculate the bearing of A's route from C.
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3 sides of a triangle are given:
CB = a = 10
CA =  b = 8
AB = c =12
Find the angle C using the Cosine Law:
c^2 = a^2 + b^2 - 2*a*b*cos(C)
144 = 100 + 64 - 2*10*8*cos(C)
cos(C) = -20/-160 = 1/8
C =~ 82.82 degs
Bearing = 150 - C =~ 67.2 degs
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I'll email a graph and method later today.