Question 1202296


A sum of money is shared among nine people
so that the first gets 75 naira next 150 naira
the next 225 naira,and so on
A.How much money does the ninth person get
B.How much money is shared altogether

The money shared is an arithmetic sequence

tn = a+(n-1)d

a= 75,  n=9  , d=75

The 9th person will get

t9 = 75+(9-1)*75

tn = 75+600
tn = 675


 ninth person gets 675 naira

Sn sum shared is thr total amount shared 


Sn = n/2(a+l)

n=9,  a =75,  l= 675

sn = 9/2 (75+675)

sn = 9/2 * 750

Sn = 9*375 = 3375

Total amount 3375 naira