Question 1202257
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In the lab, Justin has two solutions that contain alcohol and is mixing them with each other. 
He uses 3 times as much Solution A as Solution B. Solution A is 16% alcohol and Solution B 
is 11% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 
177 milliliters of pure alcohol?
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<pre>
Let x be the volume of solution B in milliliters (the quantity under the problem's question).

Then the volume of the solution A is 3x milliliters, according to the problem.


Solution B contains 0.11x milliliters of the pure alcohol.

Solution A contains 0.16*(3x) milliliters of the pure alcohol.


Write equation for the total content of the pure alcohol

    0.11x + 0.16*(3x) = 177  milliliter of the pure alcohol.


Simplify this equation and find x

    0.11x + 0.48x = 177

        0.59x     = 177

            x     = 177/0.59 = 300.


<U>ANSWER</U>.  Justin used 300 mL of solution B.
</pre>

Solved.