<PRE><B>Question 1202253</B>
.
Given that log 5=0.6990 and log 7=0.8451, evaluate 
(a) log 35 
(b) log 2.8
(c) Given that N 0.8942=2.8, use your result in (b) above to find the value of N
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&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;In this my post, &amp;nbsp;I will solve &amp;nbsp;(a) &amp;nbsp;and &amp;nbsp;(b), &amp;nbsp;ONLY.


&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;I will not solve &amp;nbsp;(c) &amp;nbsp;in order for do not make a mess from this post.



&lt;pre&gt;
(a)  35 = 5*7;  therefore log(35) = log(5*7) = log(5) + log(7) = 0.6990 + 0.8451 = 1.541.    &lt;U&gt;ANSWER&lt;/U&gt;



(b)  First, log(2) = {{{log((10/5))}}} = log(10) - log(5) = 1 - 0.6990 = 0.301.

     Next, 2.8 = {{{14/5}}} = {{{(7*2)/5}}} = log(7) + log(2) - log(5) = 0.8451 + 0.301 - 0.6990 = 0.4471.  &lt;U&gt;ANSWER&lt;/U&gt;
&lt;/pre&gt;

Solved.



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By the way, what is written in your part (c), mathematically is UNREADABLE 
and, THEREFORE, makes no sense.



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