Question 1202209
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The third question apparently from the same student in which the meaning of the question is unclear....<br>
Once the 4 letters are chosen, the number of different ways of arranging them is 4! = 24, unless both of the letters S are chosen; in that case the number of arrangements of the 4 letters is 4!/2! = 12.<br>
ANSWER: 12 if both letters S are chosen; 24 otherwise.<br>
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NOTE: The solution shown by tutor @ikleyn is very likely the question that the problem INTENDED to ask.<br>
However, the wording of the problem implies that 4 letters are chosen from the letters in PASSWORD; and then THOSE 4 LETTERS are arranged.<br>