Question 1202206

Find three consecutive integers such that -7 times the sum of the first and third is 12 greater than the product of 10 and the opposite of the second.
let the integers be x,x+1,x+2

-7*(x+x+2) = 10*-(x+1)+12

-7(2x+2) = -10x-10+12

-14x-14   = -10x+2

4x=-16
x=-4

The integers are -4, -3,-2