Question 1202194
area of rectangle = 45 square meters.
the length of the rectangle is 1 meter more than twice the width.
L = length
W = width
L = 2W + 1
A = area = 45
A = L * W
replace L with 2W + 1 to get:
A = (2W + 1) * W
simplify to get:
A = 2W^2 + W
since A = 45, equation becomes:
45 = 2W^2 + W
subtract 45 from both sides of the equation to get:
2W^2 + W - 45 = 0
factor to get:
(2W + 10) * (W - 4.5) = 0
solve for W to get:
W = -10 or W = 4.5
W can't be negative, so W = 4.5
since A = 45 and W = 4.5, then L has to be equal to 10.
L = 2W + 1 becomes 10 = 2*4.5 + 1 which becomes 10 = 10, confirming the relationship between L and W is correct.
solution is that the dimensions of the rectangle are 10 by 4.5
10 is the length.
4.5 is the width.