Question 1202168
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This is a problem that is easily solved using two basic methods.<br>
(1) Select the balls one at a time<br>
P(1st ball is red) = 5/9  (there are 9 balls of which 5 are red)
P(2nd ball is red) = 4/8  (there are 8 balls left, of which 4 are red)
P(both balls are red) = (5/9)(4/8) = (5/9)(1/2) = 5/18<br>
(2) Use "n choose r"<br>
number of ways of choosing any 2 of the 9 balls: "9 choose 2" = (9*8)/(2*1) = 72/2 = 36
number of says of choosing 2 of the 5 red balls: "5 choose 2" = (5*4)/(2*1) = 20/2 = 10<br>
P(choosing 2 of the red balls) = 10/36 = 5/18<br>