<PRE><B>Question 1202097</B>
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I just solved this problem at this forum a week ago.  See the link


https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1201990.html



For your convenience, I place this my solution here again:



   &amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;- - - - - - - - - - - - 



It can be solved in three simple steps.



&lt;pre&gt;
             Step 1 - determine how many boys are in the class


Let &quot;b&quot; be the number of boys in the class. 
Then the number of girls is (b-6).


The total students equation is

    b + (b-6) = 22,

which gives

    2b = 22 + 6,  2b = 28,  b = 28/2 = 14.  So, there are 14 boys in the class, in all.



             Step 2 - determine how many boys are the Sophomores


From total 14 boys, subtract 5 Freshmen boys and get 14-5 = 9 Sophomores boys.
   


             Step 3 - determine how many Sophomores are in the class


Add 4 Sophomore girls and 9 Sophomores boys to get 4+9 = 13 Sophomores in the class, in total.


&lt;U&gt;ANSWER&lt;/U&gt;.  There are 13 Sophomores in the class, in all.
&lt;/pre&gt;

Solved.



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