Question 115004
{{{x^2-11x=-30}}} Start with the given equation



{{{x^2-11x+30=0}}} Move all of the terms to the left side



{{{(x-6)(x-5)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:


{{{x-6=0}}} or {{{x-5=0}}}


{{{x=6}}} or {{{x=5}}}  Now solve for x in each case



So our solutions are {{{x=6}}} or {{{x=5}}}



Notice if we graph {{{y=x^2-11x+30}}} we get


{{{ graph(500,500,-10,10,-10,10, x^2-11x+30) }}}


and we can see that the graph has roots at {{{x=6}}} and {{{x=5}}}, so this verifies our answer.