Question 1202070
{{{log(1/4,64)=n}}}---------if hard to read, logarithm base one-fourth, of 64 is n.


In exponential form, {{{(1/4)^n=64}}}

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{{{(1/2^2)^n=2^6}}}

{{{(2^(-2))^n=2^6}}}

{{{2^(-2n)=2^6}}}

The same base so the exponents must be equal.
{{{-2n=6}}}

{{{n=6/(-2)}}}

{{{n=-3}}}