Question 115026
{{{sqrt( 4*a^5* b^6) /sqrt(3 *a^2* b^4* c^2)}}}….raise to the second power (you already know from relationship between exponents and radicals: the appropriate exponent will "undo" an radical, and the right power will "undo" a root.) 

{{{(sqrt(4 *a^5* b^6))^2 /(sqrt(3* a^2 *b^4 *c^2))^2}}}…...."undo" a square root
{{{4 *a^5 *b^6 /(3 *a^2* b^4* c^2) }}}….


{{{4* a^5* b^6 /(3 *a^2* b^4 *c^2) }}}….apply basic exponent rule: whenever you divide two terms with the same base, you can subtract the exponents: {{{a^m/a^n=a^(m-n)}}}

{{{4 *a^(5-2)* b^(6-4) /(3*c^2) }}}….
	
{{{4* a^3* b^2/(3*c^2) }}}….