Question 115028
ln(x-2)+ln(2x-3)=2lnx

ln[(x-2)(2x-3)] = ln(x^2)
Take the anti-log of both sides to get:
(x-2)(2x-3) = x^2
x^2-7x+6 = x^2
7x=6
x = 6/7
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Cheers,
Stan H.