Question 115026
square of 4 a^5 b^6 over the square of 3 a^2 b^4 c^2
--------
(4a^5b^6)^2 / (3a^2b^4c^2)^2

= (16/9)(a^10/a^4)(b^12/b^8)(1/c^4))

= (16/9)(a^6)(b^4)(1/c^4)

= (16a^6b^4)/(9c^4)

===============
Cheers,
Stan H.