Question 1201987
*[illustration Two_dice_rolled.png].

Here the total  possible outcomes = 36 n(S) =36

Event (A) Sum greater than 6
*[illustration Two_dice_rolled_6.png]
P(A) = n(A)/n(S) = 21/36 = 7/12

Event B: The sum  is odd number
There are 18  possible outcomes n(B)=18
P(B)= n(B)/n(S)= 18/36 = 1/2

Convert to percent  if required