<PRE><B>Question 1201986</B>
Here the total  possible outcomes = 36 n(S) =36

Event (A)  (4,6),(5,5),(5,6), (6,4),(6,5),(6,6)  n(A) = 6
P(A) = n(A)/n(S) = 6/36 = 1/6

Event B: The sum is divisible by 2 or 3 (or both).
There are 24 possible outcomes n(B)=24
P(B)= n(B)/n(S)= 24/36= 2/3

Convert to percent  if required

*[illustration Two_dice_rolled.png].

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