Question 1201969
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<pre>

Last digit (ones digit) must be one of the three possibilities 2, 4, 6.


1st digit can be any of remaining 5 digits;
2nd digit can be any of remaining 4 digits;
3rd digit can be any of remaining 3 digits;


In total, there are 3*5*4*3 = 180 such 4-digit numbers.    <U>ANSWER</U>
</pre>

Solved.



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Another reasoning is THIS:


<pre>
Without restriction on parity, 6*5*4*3 = 360 numbers are possible.


Of them, exactly half, 360/2 = 180, are even numbers.
</pre>

Two solutions for your satisfaction.