Question 115020
3X^2-6X-3=12-6X
3X^2-6X+6X-3-12=0
3X^2-15=0
3(X^2-5)=0
USING THE QUADRATIC EQUATION WE GET:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
X=(0+-SQRT[0^2-4*1*-5])/2*1
X=(+-SQRT20)/2
X=(+-4.47)/2
X=+-2.235 ANSWERS.