Question 1201954
let  x be width then 2x =length

Are of circle = pi*r^2
pi=pir^2

r^2=1

r=1 
d=2 

Apply pythagoras theorem in triangle
x^2+(2x)^2 = 2^2

5x^2=4
x^2= 4/5
x=(2)/sqrt(5)

width = (2)/sqrt(5)
length = 4/sqrt(5)
Area of rectangle = 2 * area of triangle

Area of rectangle  = 2* 1/2 * 2/sqrt(5) * 4/sqrt(5)

=8/5