Question 1201941
The length of a rectangular enclosure is twice its width. The perimeter of the enclosure is 180 metres. 
Write down two simultaneous equations and Use Cramer’s rule to determine the length and the width of the 
enclosure.

The length of a rectangular enclosure is twice its width.

let width be x and length be y

As per the condition given y=2x or y-2x =0...............(1)

Perimeter of rectangle = 2L+2w

2x+2y = 180.........................(2) (divide by 2)

-2x+y =0
x+y =90
ly, type
     *[illustration cramer.png].

By Cramer's rule x = dx/d  = -90/-3 = 30 m

and y = dy/d = -180/-3 = 60 m