<PRE><B>Question 1201937</B>
.


I will assume that your preferred tool is regular calculator TI-83 or TI-84.


&lt;pre&gt;
    (A)  p = normalcdf(36000, 56000, 75000, 15000) = 0.098.       &lt;U&gt;ANSWER&lt;/U&gt;


    (B)  p = normalcdf(85000, 9999999, 75000, 15000) = 0.2525.    &lt;U&gt;ANSWER&lt;/U&gt;


    (C)  p = 0 (or vanishingly small value)  &lt;&lt;&lt;---===  double check if you correctly posed this question. 
&lt;/pre&gt;

Solved.


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</PRE>