Question 1201922
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<pre>

ince the order of children in groups does not matter, this problem is on COMBINATIONS.


It asks how many different combinations of 6 children can be made of the group of 16 children.


The answer is  {{{C[16]^6}}} = {{{16!/(6!*10!)}}} = {{{(16*15*14*13*12*11)/(1*2*3*4*5*6)}}} = 8008.
</pre>

Solved, with explanations.


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On &nbsp;Combinations, &nbsp;see introductory lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =http://www.algebra.com/algebra/homework/Permutations/Introduction-to-Combinations-.lesson>Introduction to Combinations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =http://www.algebra.com/algebra/homework/Permutations/PROOF-of-the-formula-on-the-number-of-combinations.lesson>PROOF of the formula on the number of Combinations</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =http://www.algebra.com/algebra/homework/Permutations/Problems-on-Combinations.lesson>Problems on Combinations</A>

in this site.