Question 1201898
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A class consisting of 8 men and 7 women we're 2 selected randomly to represent the class in a dabate 
find the probability that the 2 selected are 
(a) both men 
(b) both woman 
(c) of the same Sex 
(d) of the different Sex.
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        I will not edit your post - it really bothered me to edit every post.
        I will keep your text as is, although it really needs to be edited.



<pre>
Total people is  8+7 = 15.


(a)  both men        P(both men)   = {{{(8/15)*(7/14)}}} = {{{56/210}}} = {{{4/15}}}.


(b)  both women      P(both women) = {{{(7/15)*(6/14)}}} = {{{42/210}}} = {{{3/15}}}.


(c)  of the same sex P(both men)  +  P(both women) = {{{4/15}}} + {{{3/15}}} = {{{7/15}}}.


(d)  of the different sex: the complement to the value of (c)  1 - {{{7/15}}} = {{{8/15}}}.
</pre>

Solved.


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The formulas are &nbsp;SELF-EXPLANATORY &nbsp;and intuitively clear.