Question 1201890
Because of this part,  "the sum of the first and second is", and the three integers are odd,
variables can be assigned as
n-1, n+1, n+3
.


{{{4((n-1)+(n+1))=11+3(n+3)}}}

-

{{{4(n-1+n+1)=11+3n+9}}}

{{{4(2n)=3n+20}}}

{{{8n=3n+20}}}

{{{5n=20}}}

{{{n=4}}}


The consecutive odd integers:   3, 5, 7