Question 1201880
A steel ball is projected downward at an angle of 48° with the horizontal from the top of the cliff 480 m high. Its initial velocity is 43 m/s.
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Using 10 m/sec/sec for gravity:

 
a. How long will it take before striking the ground?
The vertical component is -43*sin(48) = ~31.96 m/s
h(t) = -5t^2 - 31.96t + 480 = 0 at impact
Solve for t
*[invoke solve_quadratic_equation -5,-31.96,480]
Ignore the negative value.
t = 7.11 seconds to impact
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b. How far from the base of the building will it strike?
Horizontal component = 43*cos(48)
Distance = 7.11*43*cos(48) = ~ 204.57 meters
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c. With what velocity will it hit the ground?
Impact speed = vert comp of 43 + 5t = 31.96 + 7.11*5 = ~ 67.51 m/sec
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d. At what angle with horizontal will it strike?
The path of the object is a parabola --- h(t) = -5t^2 - 31.96t + 480 = 0 at impact.
Find the slope at t = 7.11
h'(t) = -10t - 31.96 = -103.06
Angle = 180 - h'(t) = 76.94 degs