Question 1201850
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A rocket is launched from the surface of the Earth. The surface of the Earth can be modelled 
by the equation x2+y2 = 6400 squared where the units are in km. 
The path of the rocket can be modelled by the equation y = 8000 - x2/2500.
Find the co-ordinates of where the rocket takes off and where it lands. 
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If you mean real Earth as we know it as a 3D solid in space,

then it is NOT modelled by the equation  {{{x^2}}} + {{{y^2}}} = {{{6400^2}}}.


It is modelled by equation  {{{x^2}}} + {{{y^2}}} + {{{z^2}}} = {{{6400^2}}}.


So, I can not consider your "problem" seriously.


If you mean something different from my interpretation, then your wording should/must be precise and adequate.
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