Question 1201760
r, radius of base, same as radius of cylinder


{{{pi*r^2}}}, base area


If h is height of cylinder, description gives {{{2pi*r*h=4pi*r^2}}}, and you can solve for h.



Further Review:
{{{2pi*r}}}, the distance around the cylinder
h, the length of the cylinder
{{{2pi*r*h}}}, the lateral area of the cylinder.


You were given that this lateral area is {{{4*pi*r^2}}}.
Also according to description,  {{{2pi*r*h=4*pi*r^2}}}.
SOLVE FOR h.  That is the answer to the question!  Do this correctly, and the result will match one of your choices.


{{{2pi*r*h=4pi*r^2}}}

{{{(1/(2pi*r))2pi*r*h=(1/(2pi*r))4pi*r^2}}}

{{{(1/(2pi*r))2pi*r*h=(1/(2pi*r))2*2pi*r^2}}}

{{{(1/(cross(2pi*r)))cross(2pi*r)*h=(1/(cross(2pi*r)))2*cross(2pi*r)*r}}}
You understand how this works?