Question 113860

{{{2x^2-3x=0}}}


{{{x(2x-3)=0}}} Factor out the GCF x



Now set each factor equal to zero:


{{{x=0}}} or {{{2x-3=0}}}


{{{x=0}}} or {{{x=3/2}}}  Now solve for x in each case



So our solutions are {{{x=0}}} or {{{x=3/2}}}



Notice if we graph {{{y=2x^2-3x}}} we get


{{{ graph(500,500,-10,10,-10,10, 2x^2-3x) }}}


and we can see that the graph has roots at {{{x=0}}} and {{{x=3/2}}}, so this verifies our answer.