Question 114938
x intercepts:

Set f(x) equal to zero and solve for x


{{{0= (9-x^2)/(x^2-4x-4)}}}


{{{9-x^2=0}}} This means the numerator is equal to zero. The denominator is never zero


{{{9=x^2}}} Add x^2 to both sides


When taking the square root, we get the answers {{{x=-3}}} or {{{x=3}}}


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y-intercepts:


Simply plug in x=0 and solve for y



{{{f(0)= (9-0^2)/(0^2-4(0)-4)}}}




{{{f(0)= -9/4}}} Simplify



So the y-intercept is {{{ -9/4}}}