Question 1201443
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The tutor @math_helper has provided a great solution.


I'll mention a slightly different pathway.


We can use the nCr combination formula<ul><li>x = 4C4 = 1 way to select the four jacks in any order.</li><li>y = 48C1 = 48 ways to select the fifth non-jack card</li></ul>x*y = 1*48 = <font color=red size=4>48</font> different five-card hands that consist of all four jacks.


A few references about the nCr formula
<a href = "https://mathworld.wolfram.com/Combination.html">https://mathworld.wolfram.com/Combination.html</a>
<a href = "https://www.mathsisfun.com/combinatorics/combinations-permutations.html">https://www.mathsisfun.com/combinatorics/combinations-permutations.html</a>
<a href = "https://www.calculatorsoup.com/calculators/discretemathematics/combinations.php">https://www.calculatorsoup.com/calculators/discretemathematics/combinations.php</a>


Here is another question about card hands
<a href = "https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1201482.html">https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1201482.html</a>
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