Question 1201470
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Divide ((3x-2)(x-4)-(x-4)(6-5x))/((4-x)(8x-1))
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First, transform the numerator

    (3x-2)(x-4)-(x-4)(6-5x) = (x-4)*[(3x-2) - (6-5x)] = (x-4)*(3x+5x -2-6) = (x-4)*(8x-8).


Now divide the numerator by the denominator and cancel the common factor on the way.


You will get the final answer  {{{-(8x-8)/(8x-1)}}},  or  {{{-8*((x-1)/(8x-1))}}}.


Choose any of the two expressions - they are equivalent.
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Done.