Question 1201435

x5-17x3+16x=0


⇒x5-17x3+16x=0


⇒x(x4-17x2+16)=0


⇒x(x4-x2-16x2+16)=0


⇒x(x2(x2-1)-16(x2-1))=0


⇒x(x2-1)(x2-16)=0


x(x+1)(x-1)(x2-4)=0


x(x+1)(x-1)(x+2)(x-2)=0


x=0or(x-1)=0or(x+1)=0or(x-4)=0or(x+4)=0