Question 1201398
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The percentages add to 100%, so let's say 100 games total had been played.


Each percentage corresponds to the whole number value shown here<ul><li>Jennifer won 30 games</li><li>Grace won 25 games</li><li>Janet won 45 games</li></ul>Simply erase the percent sign.


Divide each value over 100 and reduce the fraction.<ul><li>Jennifer: 30/100 = (10*3)/(10*10) = 3/10</li><li>Grace: 25/100 = (25*1)/(25*4) = 1/4</li><li>Janet: 45/100 = (5*9)/(5*20) = 9/20</li></ul>The reduced fractions are
3/10, 1/4, 9/20


The LCD is 20, so let's rewrite each denominator in terms of the LCD<ul><li>Jennifer: 3/10 = (3*2)/(10*2) = <font color=red>6</font>/20</li><li>Grace: 1/4 = (1*5)/(4*5) = 5/20</li><li>Janet: 9/20 = 9/20</li></ul>If 20 games were played, then,<ul><li>Jennifer won <font color=red>6</font>/20 of those games. <font color=red>She won 6 games</font>.</li><li>Grace won 5/20 of those games. She won 5 games.</li><li>Janet won 9/20 of those games. She won 9 games.</li></ul>This scenario represents the fewest number of games played.
This is because the nature of the LCD is to go for the lowest denominator, i.e. lowest number of games in this case.


Answer: <font color=red size=4>6</font>


This method is probably a bit more convoluted, so it might be more effective to use another route. 
But it's always a good idea to have multiple pathways.
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